document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65918>Question 65918</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve for x:  2^(x+2) + 2^x =160\r<BR>\n" );
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document.write( "im not sure what to do, can someone help me?? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46681 by </B><A HREF=/tutors/aboutme.mpl?userid=uma><B>uma(370)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uma><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46681\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given that 2^(x+2) + 2^x = 160\r<BR>\n" );
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document.write( "==> (2^x)*(2^2) + 2^x = 160  [ as x^(a + b) = x^a * x^b]\r<BR>\n" );
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document.write( "==> 2^x (2^2 + 1) = 160  [removing 2^x as common factor]\r<BR>\n" );
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document.write( "==> 2^x (4 + 1) = 160\r<BR>\n" );
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document.write( "==> 2^x(5) = 160\r<BR>\n" );
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document.write( "==> 2^x = 160/5  [dividing by 5 throughout]<BR>\n" );
document.write( "==> 2^x = 32<BR>\n" );
document.write( "==> 2^x = 2^5   [as 32 = 2^5]\r<BR>\n" );
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document.write( "as the bases are the same we equate the exponents.\r<BR>\n" );
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document.write( "==> x = 5\r<BR>\n" );
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document.write( "Good Luck!!! </SPAN>\n" );
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