document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=766269>Question 766269</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Dear Sir/Madam,\r<BR>\n" );
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document.write( "Please help me with this equation:  [(1)/(2z+i)]+[(1)/(2z-1)]=[(1)/(z+2i)] I know that I will be multiplying the equation by the least common denominator but how will I use the quadratic formula in arriving to the final answer?  Thank you very much for your help and kindness. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #466780 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=466780\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Please help me with this equation: [(1)/(2z+i)]+[(1)/(2z-1)]=[(1)/(z+2i)] I know that I will be multiplying the equation by the least common denominator but how will I use the quadratic formula in arriving to the final answer? Thank you very much for your help and kindness.<BR>\n" );
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document.write( "[(1)/(2z+i)]+[(1)/(2z-1)]=[(1)/(z+2i)] <BR>\n" );
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document.write( "Multiply thru by (2z+i)(2z-1)(z+2i) to get:<BR>\n" );
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document.write( "(2z-10)(z+2i) + (2z+i)(z+2i) = (2z+i)(2z-1)<BR>\n" );
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document.write( "2z^2 +4zi-10z-20i + 2z^2+4zi+zi-2 = 4z^2-2z+2zi-i<BR>\n" );
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document.write( "4z^2 + 9zi -10z -20i -2 = 4z^2 -2z + 2zi -i<BR>\n" );
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document.write( "7zi - 8z -19i -2  = 0<BR>\n" );
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document.write( "z(7i-8)  = 2+19i<BR>\n" );
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document.write( "z = (2+19i)/(-8+7i)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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