document.write( "Question 766185: \"A car speeds up from 40km/h to 55km/h to overtake a truck. If tthis requires 15s, what is the acceleration and distance traveled by the car?\" HELP ME PLEASE
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Algebra.Com's Answer #466723 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "===================================================================== \n" ); document.write( "acceleration is measured in meters per second per second \n" ); document.write( "acceleration = change of velocity / time taken \n" ); document.write( "change in velocity is 55 - 40 = 15 kilometers per hour = 15 / 3600 = .004 km / sec = .004 km/sec * 1000 meters/km = 4 meters /sec/sec \n" ); document.write( "time taken is 15 seconds \n" ); document.write( "acceleration = 4 / 15 = .27 meters per second / second \n" ); document.write( "======================================================================= \n" ); document.write( "distance traveled = initial velocity * time + (acceleration * time^2 / 2) \n" ); document.write( "distance traveled = 40 * 15 + (.27 * 15^2 / 2) \n" ); document.write( "note here convert 40 km /hr to 40/3600 = .01 km/sec and 1000 meters = 1km \n" ); document.write( "distance traveled = (10 meters per second * 15) + 30.38 = 180.38 meters \n" ); document.write( "==============================================================================\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |