document.write( "Question 766122: Give the quadratic equation whose roots are twice as large as the roots of the given equation: ax^2+bx+c=0 a is not equal to 0. \n" ); document.write( "
Algebra.Com's Answer #466688 by subudear(62)\"\" \"About 
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quadratic equation whose roots are twice of the given equation
\n" ); document.write( "ax^2+bx+c=0\r
\n" ); document.write( "\n" ); document.write( "is\r
\n" ); document.write( "\n" ); document.write( "ax^2+2bx+4c=0\r
\n" ); document.write( "\n" ); document.write( "You can derive using following-
\n" ); document.write( "Roots for the equation ax^2+bx+c=0 are given by\r
\n" ); document.write( "\n" ); document.write( "X1 = [-b + sqrt(b^2-4ac)]/2a
\n" ); document.write( "X2 = [-b - sqrt(b^2-4ac)]/2a\r
\n" ); document.write( "\n" ); document.write( "The new roots are twice of these roots
\n" ); document.write( "Y1 = 2X1 = 2/2a
\n" ); document.write( "Y2 = 2X2 = 2/2a\r
\n" ); document.write( "\n" ); document.write( "or\r
\n" ); document.write( "\n" ); document.write( "you can derive the equation by resolving below-\r
\n" ); document.write( "\n" ); document.write( "(x - Y1)*(x - Y2) = 0
\n" ); document.write( "(x - [-b + sqrt(b^2-4ac)]/a)*(x - [-b - sqrt(b^2-4ac)]/a) = 0
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