document.write( "Question 766123: speed of water in certain river is 6kmph and it takes a boat four times as long to row up as to row down the river. what is the speed of boat in still water?
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Algebra.Com's Answer #466675 by subudear(62)\"\" \"About 
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Let speed of water in river be u kmph
\n" ); document.write( "Let speed of boat in still water (water not moving) be v kmph\r
\n" ); document.write( "\n" ); document.write( "then time taken by boat to row DOWN the river will be\r
\n" ); document.write( "\n" ); document.write( "t*(v + u) = d ...(1)\r
\n" ); document.write( "\n" ); document.write( "t = time taken to row down, speed of boat will be (u+v) as flowing water will help boat go fast, d=distance traveled down stream \r
\n" ); document.write( "\n" ); document.write( "Similarly time time taken by boat to row UP the river will be\r
\n" ); document.write( "\n" ); document.write( "4t*(v - u) = d .....(2)\r
\n" ); document.write( "\n" ); document.write( "t = time taken to row UP which is 4 times the time taken to row DOWN, speed of boat will be (v - u) as flowing water will slowdown the boat, d=distance traveled down stream \r
\n" ); document.write( "\n" ); document.write( "As distance is same so equating both equations\r
\n" ); document.write( "\n" ); document.write( "t*(v + u) = 4t*(v - u)\r
\n" ); document.write( "\n" ); document.write( "This gives 5*u = 3*v\r
\n" ); document.write( "\n" ); document.write( "Now it is given that water speed is 6 kmph which means u = 6 kmph\r
\n" ); document.write( "\n" ); document.write( "substituting the value we get \r
\n" ); document.write( "\n" ); document.write( "v = 10 kmph\r
\n" ); document.write( "\n" ); document.write( "Speed of boat in still water is 10 kmph
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