document.write( "Question 766087: An invester invested a total of $1,800 in two mutual funds. One fund earned a 6% profit and the other earned a 3% profit. If the invester's total profit was $90 how much was invested in each mutual fund\r
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document.write( "What I think was invested in the mutual fund with 6%= $630
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document.write( "What I think was invested in the mutual fund with 3%= $1,170\r
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document.write( "am i correct or am I wrong if wrong help me understand please. \n" );
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Algebra.Com's Answer #466659 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Part I 6.00% per annum ------------- Amount invested =x \n" ); document.write( "Part II 3.00% per annum ------------ Amount invested = y \n" ); document.write( " 1800 \n" ); document.write( "Interest----- 90.00 \n" ); document.write( " \n" ); document.write( "Part I 6.00% per annum ---x \n" ); document.write( "Part II 3.00% per annum ---y \n" ); document.write( "Total investment \n" ); document.write( "x + 1 y= 1800 -------------1 \n" ); document.write( "Interest on both investments \n" ); document.write( "6.00% x + 3.00% y= 90 \n" ); document.write( "Multiply by 100 \n" ); document.write( "6 x + 3 y= 9000.00 --------2 \n" ); document.write( "Multiply (1) by -6 \n" ); document.write( "we get \n" ); document.write( "-6 x -6 y= -10800.00 \n" ); document.write( "Add this to (2) \n" ); document.write( "0 x -3 y= -1800 \n" ); document.write( "divide by -3 \n" ); document.write( " y = 600 \n" ); document.write( "Part I 6.00% $ 1200 \n" ); document.write( "Part II 3.00% $ 600 \n" ); document.write( " \n" ); document.write( "CHECK \n" ); document.write( "1200 --------- 6.00% ------- 72.00 \n" ); document.write( "600 ------------- 3.00% ------- 18.00 \n" ); document.write( "Total -------------------- 90.00 \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |