document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=766071>Question 766071</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how to find the radius of a circle with a known chord length. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #466650 by </B><A HREF=/tutors/aboutme.mpl?userid=reviewermath><B>reviewermath(1029)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=reviewermath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=reviewermath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=466650\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Q:<BR>\n" );
document.write( "how to find the radius of a circle with a known chord length.<BR>\n" );
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document.write( "A:<BR>\n" );
document.write( "Given the length of the chord, the length of the radius depends on the distance of the chord from the center of the circle.<BR>\n" );
document.write( "<b>Example:</b> The length of the chord is 8 cm and its distance from the center of the circle is 3 cm, then we use Pythagorean Theorem to find the length of the radius.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28+275%2C+275%2C+-8%2C+8%2C+-8%2C+8%2C++circle%280%2C0%2C5%29%2C+line%28-4%2C-3%2C4%2C-3%29%2C+line%280%2C0%2C4%2C-3%29%2C+line%280%2C0%2C0%2C-3%29%2C+locate%28-0.75%2C-1%2C%22y%22%29%2C+locate%282%2C-0.5%2C%22r%22%29%2C+locate%281%2C-2%2C%22x%22%29%2C+line%280%2C-2.5%2C0.5%2C-2.5%29%2C+line%280.5%2C-2.5%2C0.5%2C-3%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x is half the length of the chord.<BR>\n" );
document.write( "Using Pythagorean Theorem:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2+%2B+y%5E2+=+r%5E2 ALIGN=MIDDLE  ALT=\"x%5E2+%2B+y%5E2+=+r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r+=+sqrt%28x%5E2+%2B+y%5E2%29+ ALIGN=MIDDLE  ALT=\"r+=+sqrt%28x%5E2+%2B+y%5E2%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r+=+sqrt%284%5E2+%2B+3%5E2%29+=+sqrt%2825%29+=+5+ ALIGN=MIDDLE  ALT=\"r+=+sqrt%284%5E2+%2B+3%5E2%29+=+sqrt%2825%29+=+5+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The length of the radius is 5 cm.\r<BR>\n" );
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