document.write( "Question 766036: Write the ellipse in standard form: 12x^2+6y^2=168 \n" ); document.write( "

Algebra.Com's Answer #466619 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( "standard form: $\"%28x-h%29%5E2%2Fa%5E2%2B%28y-k%29%5E2%2Fb%5E2=1\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"12x%5E2%2B6y%5E2=168\"$ ......both sides divide by $\"168\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"12x%5E2%2F168%2B6y%5E2%2F168=168%2F168\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"cross%2812%29x%5E2%2Fcross%28168%2914%2Bcross%286%29y%5E2%2Fcross%28168%2928=1\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x%5E2%2F14%2By%5E2%2F28=1\"$ ....standard form\r
\n" ); document.write( "\n" ); document.write( "so, $\"h=0\"$ , $\"k=0\"$ , $\"a=3.74\"$ , $\"b=5.29\"$ \r
\n" ); document.write( "\n" ); document.write( "center at ( $\"0\"$ , $\"0\"$ )\r
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