document.write( "Question 766031: Would you please solve this problem:\r
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document.write( "Q3: A large department store chain is considering opening a new store in a town of 15,000 people. Before making the decision, a market survey is conducted. Of 200 persons interviewed, 165 indicated they would patronize the new store. Find a 95% confidence interval on the proportion p of people who will patronize the store. Use this to give a 95% confidence interval on the number of people who will patronize the store.\r
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document.write( "Thanks
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document.write( "Yazan \n" );
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Algebra.Com's Answer #466607 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A large department store chain is considering opening a new store in a town of 15,000 people. Before making the decision, a market survey is conducted. Of 200 persons interviewed, 165 indicated they would patronize the new store. Find a 95% confidence interval on the proportion p of people who will patronize the store. Use this to give a 95% confidence interval on the number of people who will patronize the store. \n" ); document.write( "----------- \n" ); document.write( "sample proportion:: 165/200 = 0.825 \n" ); document.write( "---- \n" ); document.write( "ME: 1.96*sqrt[0.825*0.175/200] = 0.0527 \n" ); document.write( "----- \n" ); document.write( "95% CI: 0.825-0.0527 < P < 0.825+0.0527 \n" ); document.write( "------ \n" ); document.write( "95% CI: 0.772 < p < 0.878 \n" ); document.write( "------- \n" ); document.write( "Expexted # of patrons:: \n" ); document.write( "0.772*15000 < x < 0.878*15000 \n" ); document.write( "---- \n" ); document.write( "11580 < x < 13155 \n" ); document.write( "======================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============== \n" ); document.write( " \n" ); document.write( " |