document.write( "Question 765938: a speeding boat travelled a distance of x km at a constant speed of 80km/h. an ocean liner travelled the same distance at 60 km/h. if the difference in time taken was 2 hours, calculate x. \n" ); document.write( "

Algebra.Com's Answer #466520 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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a speeding boat travelled a distance of x km at a constant speed
\n" ); document.write( " of 80km/h.
\n" ); document.write( " an ocean liner travelled the same distance at 60 km/h.
\n" ); document.write( " if the difference in time taken was 2 hours, calculate x.
\n" ); document.write( ":
\n" ); document.write( "Write a time equation; time = dist/speed
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\n" ); document.write( "liner time - boat time = 2 hrs
\n" ); document.write( " $\"x%2F60\"$ - $\"x%2F80\"$ = 2
\n" ); document.write( "multiply equation by 240, resulting in
\n" ); document.write( "4x - 3x = 480
\n" ); document.write( "x = 480 km is the distance
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\n" ); document.write( "Check this by finding the time of each
\n" ); document.write( "480/60 = 8 hrs
\n" ); document.write( "480/80 = 6 hrs, a diff of 2 hrs \n" ); document.write( "

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