document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=765786>Question 765786</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A ladder leaning against a wall makes a 60 degrees angle with the ground.  The base of the ladder is 4m from the building.  How high above the ground is the top of the ladder?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #466509 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=466509\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Right angled triangle.<BR>\n" );
document.write( "Base = 4m<BR>\n" );
document.write( "Angle with ground = 60 degrees<BR>\n" );
document.write( "Height of top of ladder is found by<BR>\n" );
document.write( "tan  = Opposite/Adjacent<BR>\n" );
document.write( "tan (60) = Opposite/4<BR>\n" );
document.write( "Opposite = 4 + tan(60) = 6.9m<BR>\n" );
document.write( "This is the height of the top of<BR>\n" );
document.write( "ladder above ground.<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
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