document.write( "Question 765866: Ice weighs 62.4lbs per cubic ft. Find approximate weight of the figures:
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document.write( "A) 22ft x 15ft x 4ft
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document.write( "B) 2 cylindrical pilars, each has diameter of 1ft x 9ft
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document.write( "C) 4 spheres, largest sphere has diameter of 4ft other 3 diametets are 2ft, 1ft, 1/2ft\r
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document.write( "Round weights to nearest tenth \n" );
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Algebra.Com's Answer #466503 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! A) Using formula: length*width*height \n" ); document.write( "= 1320ft^3 \n" ); document.write( "1320 * 62.4 = 823681bs \n" ); document.write( "...................... \n" ); document.write( "B) Using formula: (Pi*r^2*h)*2 (height = 9ft) \n" ); document.write( "= 14.1ft^3 \n" ); document.write( "14.1 * 62.4 = 879.8lbs \n" ); document.write( "........................ \n" ); document.write( "C) Using formula: 4/3*Pi*r^3 \n" ); document.write( "Diam = 4ft = 33.51ft^3 \n" ); document.write( "33.51 * 62.4 = 2091.0lbs \n" ); document.write( "Diam = 2ft = 4.19ft^3 \n" ); document.write( "4.19*62.4 = 261.5lbs \n" ); document.write( "Diam = 1ft = 0.52ft^3 \n" ); document.write( "0.52 * 62.4 = 32.5lbs \n" ); document.write( "Diam = 1/2ft = 0.07ft^3 \n" ); document.write( "0.07 * 62.4 = 4.4lbs \n" ); document.write( "Hope this helps. \n" ); document.write( ":-) \n" ); document.write( " |