document.write( "Question 765882: The sum of 4 consecutive multiples of 12 have a sum of 216. What is the greatest of these numbers? \n" ); document.write( "
Algebra.Com's Answer #466494 by suruman(21)![]() ![]() You can put this solution on YOUR website! There are 4 consecutive multiples of 12. \n" ); document.write( "Let the consecutive numbers be: \n" ); document.write( "12*(n-1), 12*(n),12*(n+1) and 12*(n+2). \n" ); document.write( "Sum of the consecutive numbers equals 216. \n" ); document.write( "Thus, \n" ); document.write( "12 * {(n-1)+(n)+(n+1)+(n+2) } = 216 \n" ); document.write( "(3*n)+(n+2)=216/12 = 18 \n" ); document.write( "4*n + 2 = 18 \n" ); document.write( "4*n = 16 \n" ); document.write( "n=16/4 = 4 \n" ); document.write( "Hence the greatest of these numbers = 12*(n+2) = 12*(4+2) = 12*6 = 72. \n" ); document.write( " \n" ); document.write( " |