document.write( "Question 765882: The sum of 4 consecutive multiples of 12 have a sum of 216. What is the greatest of these numbers? \n" ); document.write( "
Algebra.Com's Answer #466494 by suruman(21)\"\" \"About 
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There are 4 consecutive multiples of 12.
\n" ); document.write( "Let the consecutive numbers be:
\n" ); document.write( "12*(n-1), 12*(n),12*(n+1) and 12*(n+2).
\n" ); document.write( "Sum of the consecutive numbers equals 216.
\n" ); document.write( "Thus,
\n" ); document.write( "12 * {(n-1)+(n)+(n+1)+(n+2) } = 216
\n" ); document.write( "(3*n)+(n+2)=216/12 = 18
\n" ); document.write( "4*n + 2 = 18
\n" ); document.write( "4*n = 16
\n" ); document.write( "n=16/4 = 4
\n" ); document.write( "Hence the greatest of these numbers = 12*(n+2) = 12*(4+2) = 12*6 = 72.
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