document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=765908>Question 765908</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man is four time as old as his som the different between their ages is 36 years. Find the sum of their ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #466491 by </B><A HREF=/tutors/aboutme.mpl?userid=suruman><B>suruman(21)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=suruman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=suruman><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=466491\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let age of son be S.<BR>\n" );
document.write( "Since the man is four times as old the age of his son, his age =4*S<BR>\n" );
document.write( "Difference between their age is 36 years.<BR>\n" );
document.write( "Therefore,<BR>\n" );
document.write( "4*S - S = 36<BR>\n" );
document.write( "3*S=36<BR>\n" );
document.write( "S=12, that is, age of son is 12 years.\r<BR>\n" );
document.write( "\n" );
document.write( "Age of the man = 4*S = 4*12 = 48.<BR>\n" );
document.write( "Sum of their ages = 48 + 12 = 60.<BR>\n" );
document.write( " </SPAN>\n" );
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