document.write( "Question 765853: 42 is divided into two parts such that five times the second part exceeds four time the first part by 48.find the first part and second part respectively. \n" ); document.write( "
Algebra.Com's Answer #466453 by josgarithmetic(39620)\"\" \"About 
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Two parts, m and n. \r
\n" ); document.write( "\n" ); document.write( "\"m%2Bn=42\"\r
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\n" ); document.write( "\n" ); document.write( "\"5n=4m%2B48\", \"five times the second part exceeds four time the first part by 48.\"
\n" ); document.write( "Five times the second part is 5n.
\n" ); document.write( "Four times the first part is 4m.
\n" ); document.write( "Exceeding 4m by 48 is 4m+48.\r
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\n" ); document.write( "\n" ); document.write( "The choice is yours how to solve the two equations for m and n. Maybe try m=42-n and substitute; \"5n=4%2842-n%29%2B48\" and simplify to solve first for n...
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\n" ); document.write( "\"5n=168-4n%2B48\"
\n" ); document.write( "\"9n=168%2B48=216\"
\n" ); document.write( "\"highlight%28n=24%29\"
\n" ); document.write( "therefore \"highlight%28m=18%29\"
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