document.write( "Question 765841: how would i graph this equation... x-2y=-2 \n" ); document.write( "
Algebra.Com's Answer #466449 by MathLover1(20849)\"\" \"About 
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Solved by pluggable solver: Graphing Linear Equations

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\n" ); document.write( " \"1%2Ax-2%2Ay=-2\"Start with the given equation
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\n" ); document.write( " \"-2%2Ay=-2-1%2Ax\" Subtract \"1%2Ax\" from both sides
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\n" ); document.write( " \"y=%28-1%2F2%29%28-2-1%2Ax%29\" Multiply both sides by \"-1%2F2\"
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\n" ); document.write( " \"y=%28-1%2F2%29%28-2%29%2B%281%2F2%29%281%29x%29\" Distribute \"-1%2F2\"
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\n" ); document.write( " \"y=2%2F2%2B%281%2F2%29x\" Multiply
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\n" ); document.write( " \"y=%281%2F2%29%2Ax%2B2%2F2\" Rearrange the terms
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\n" ); document.write( " \"y=%281%2F2%29%2Ax%2B1\" Reduce any fractions
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\n" ); document.write( " So the equation is now in slope-intercept form (\"y=mx%2Bb\") where \"m=1%2F2\" (the slope) and \"b=1\" (the y-intercept)
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\n" ); document.write( " So to graph this equation lets plug in some points
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\n" ); document.write( " Plug in x=-8
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\n" ); document.write( " \"y=%281%2F2%29%2A%28-8%29%2B1\"
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\n" ); document.write( " \"y=-8%2F2%2B1\" Multiply
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\n" ); document.write( " \"y=-6%2F2\" Add
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\n" ); document.write( " \"y=-3\" Reduce
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\n" ); document.write( " So here's one point (-8,-3)
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\n" ); document.write( " Now lets find another point
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\n" ); document.write( " Plug in x=-6
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\n" ); document.write( " \"y=%281%2F2%29%2A%28-6%29%2B1\"
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\n" ); document.write( " \"y=-6%2F2%2B1\" Multiply
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\n" ); document.write( " \"y=-4%2F2\" Add
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\n" ); document.write( " \"y=-2\" Reduce
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\n" ); document.write( " So here's another point (-6,-2). Add this to our graph
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\n" ); document.write( " Now draw a line through these points
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\n" ); document.write( " So this is the graph of \"y=%281%2F2%29%2Ax%2B1\" through the points (-8,-3) and (-6,-2)
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\n" ); document.write( " So from the graph we can see that the slope is \"1%2F2\" (which tells us that in order to go from point to point we have to start at one point and go up 1 units and to the right 2 units to get to the next point) the y-intercept is (0,\"1\")and the x-intercept is (\"-2\",0) . So all of this information verifies our graph.
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\n" ); document.write( " We could graph this equation another way. Since \"b=1\" this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,\"1\").
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\n" ); document.write( " So we have one point (0,\"1\")
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\n" ); document.write( " Now since the slope is \"1%2F2\", this means that in order to go from point to point we can use the slope to do so. So starting at (0,\"1\"), we can go up 1 units
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\n" ); document.write( " and to the right 2 units to get to our next point
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\n" ); document.write( " Now draw a line through those points to graph \"y=%281%2F2%29%2Ax%2B1\"
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\n" ); document.write( " So this is the graph of \"y=%281%2F2%29%2Ax%2B1\" through the points (0,1) and (2,2)
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