document.write( "Question 764802: the sum of twice a first number and five times a second number is 90. if the second number is subtracted from five times the second number the result is 36. find the numbers. \n" ); document.write( "
Algebra.Com's Answer #466420 by explodingstxrs(1)\"\" \"About 
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Are you sure it's \"the second number is subtracted from five times the second number\"?
\n" ); document.write( "If so; let's make 1st number = A and 2nd number B\r
\n" ); document.write( "\n" ); document.write( "Elimination\r
\n" ); document.write( "\n" ); document.write( "2a + 5b = 90
\n" ); document.write( "5b - b = 36
\n" ); document.write( "--------------------\r
\n" ); document.write( "\n" ); document.write( "2a + 5b = 90...... (1)
\n" ); document.write( "0a + 4b = 36...... (2)
\n" ); document.write( "-------------------
\n" ); document.write( "In this case, we want to eliminate b (find the value of a) so multiply (1) with 4 and multiply (2) with 5\r
\n" ); document.write( "\n" ); document.write( "8a + 20b = 360
\n" ); document.write( "0a + 20b = 144
\n" ); document.write( "------------------------- -
\n" ); document.write( "8a = 216
\n" ); document.write( "a = 27\r
\n" ); document.write( "\n" ); document.write( "Substitute a to (1)
\n" ); document.write( "2(27) + 5b = 90
\n" ); document.write( "54 + 5b = 90
\n" ); document.write( "b = 36/5
\n" ); document.write( "b = 7,2\r
\n" ); document.write( "\n" ); document.write( "Hope this help :-)
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