document.write( "Question 764802: the sum of twice a first number and five times a second number is 90. if the second number is subtracted from five times the second number the result is 36. find the numbers. \n" ); document.write( "
Algebra.Com's Answer #466420 by explodingstxrs(1)![]() ![]() ![]() You can put this solution on YOUR website! Are you sure it's \"the second number is subtracted from five times the second number\"? \n" ); document.write( "If so; let's make 1st number = A and 2nd number B\r \n" ); document.write( "\n" ); document.write( "Elimination\r \n" ); document.write( "\n" ); document.write( "2a + 5b = 90 \n" ); document.write( "5b - b = 36 \n" ); document.write( "--------------------\r \n" ); document.write( "\n" ); document.write( "2a + 5b = 90...... (1) \n" ); document.write( "0a + 4b = 36...... (2) \n" ); document.write( "------------------- \n" ); document.write( "In this case, we want to eliminate b (find the value of a) so multiply (1) with 4 and multiply (2) with 5\r \n" ); document.write( "\n" ); document.write( "8a + 20b = 360 \n" ); document.write( "0a + 20b = 144 \n" ); document.write( "------------------------- - \n" ); document.write( "8a = 216 \n" ); document.write( "a = 27\r \n" ); document.write( "\n" ); document.write( "Substitute a to (1) \n" ); document.write( "2(27) + 5b = 90 \n" ); document.write( "54 + 5b = 90 \n" ); document.write( "b = 36/5 \n" ); document.write( "b = 7,2\r \n" ); document.write( "\n" ); document.write( "Hope this help :-) \n" ); document.write( " |