document.write( "Question 765749: At one boat dealer, she found a boat she likes that sells for $15,000 and depreciates at a rate of
\n" );
document.write( "30% per year. What will be the value of the boat after 3 years? \n" );
document.write( "
Algebra.Com's Answer #466375 by MathLover1(20849)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "you can do it this way:\r \n" ); document.write( "\n" ); document.write( "In the problem you are given the rate of decrease of \n" ); document.write( "\n" ); document.write( "Each year, the boat is worth \n" ); document.write( "\n" ); document.write( "$ \n" ); document.write( "\n" ); document.write( "next year value \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "and finally, \r \n" ); document.write( "\n" ); document.write( "$ \n" ); document.write( "\n" ); document.write( "$ \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "or use exponential growth/decay formula:\r \n" ); document.write( "\n" ); document.write( "Since the decay equation takes on the form \n" ); document.write( "Plugging this into the equation, we have \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So after 3 years, the car will be worth \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |