document.write( "Question 765635: The sum of the squares of two numbers is 4 and the difference of the squares of those two numbers is 1. Find the two numbers.\r
\n" ); document.write( "\n" ); document.write( "I think the two equations are:
\n" ); document.write( "Let the numbers be x and y
\n" ); document.write( "x(square) + y(square) = 4
\n" ); document.write( "x(square) - y(square) = 1\r
\n" ); document.write( "\n" ); document.write( "That is the equations that i got but the answer is a decimal...
\n" ); document.write( "I'm also not sure about the answer and the equation... please help\r
\n" ); document.write( "\n" ); document.write( "Thanks
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Algebra.Com's Answer #466289 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
x^2+y^2=4
\n" ); document.write( "x^2-y^2=1\r
\n" ); document.write( "\n" ); document.write( "add the two equations\r
\n" ); document.write( "\n" ); document.write( "2x^2=5
\n" ); document.write( "/2
\n" ); document.write( "x^2=5/2\r
\n" ); document.write( "\n" ); document.write( "x= +/- (5/2)\r
\n" ); document.write( "\n" ); document.write( "plug x=(5/2) in the first equations
\n" ); document.write( "(5/2)^2+y^2=4\r
\n" ); document.write( "\n" ); document.write( "25/4 +y^2=4
\n" ); document.write( "y^2=4-(25/4)\r
\n" ); document.write( "\n" ); document.write( "y^2=-(9/4)\r
\n" ); document.write( "\n" ); document.write( "y=(3/2)I
\n" ); document.write( "x=(5/2) , y= (3/2)i\r
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