document.write( "Question 65845This question is from textbook An Incremental Development
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document.write( ": Solve\r
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document.write( "x + y + z = 5\r
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document.write( "x - 2y + z = 8\r
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document.write( "3x - y - z = 3 \n" );
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Algebra.Com's Answer #46628 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Solve \n" ); document.write( "(1) x + y + z = 5 \n" ); document.write( "(2) x - 2y + z = 8 \n" ); document.write( "(3) 3x - y - z = 3\r \n" ); document.write( "\n" ); document.write( "Lets add eq (1) & (3) and we get:\r \n" ); document.write( "\n" ); document.write( "4x=8 \n" ); document.write( "x=2\r \n" ); document.write( "\n" ); document.write( "Substitute x=2 in Eq (1) & (2) and we have:\r \n" ); document.write( "\n" ); document.write( "(1) 2 + y + z = 5 \n" ); document.write( "(2) 2 - 2y + z = 8 \r \n" ); document.write( "\n" ); document.write( "subtract (2) from (1) getting:\r \n" ); document.write( "\n" ); document.write( "3y=-3 \n" ); document.write( "y=-1\r \n" ); document.write( "\n" ); document.write( "Substitute x=2 and y=-1 in (1) and we have:\r \n" ); document.write( "\n" ); document.write( "(1) 2 + (-1) + z = 5 \n" ); document.write( "1+z=5 subtract 1 from both sides: \n" ); document.write( "z=4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Ck by substituting x=2, y=-1 and z=4 in the original eqs.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |