document.write( "Question 764698:
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document.write( "Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B? \n" );
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Algebra.Com's Answer #466279 by nuAge tutors(1)![]() ![]() ![]() You can put this solution on YOUR website! Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).\r \n" ); document.write( "\n" ); document.write( "Then, x x 14 x 2 + (13900 - x) x 11 x 2 = 3508 \n" ); document.write( "100 100 \n" ); document.write( " 28x - 22x = 350800 - (13900 x 22)\r \n" ); document.write( "\n" ); document.write( " 6x = 45000\r \n" ); document.write( "\n" ); document.write( " x = 7500.\r \n" ); document.write( "\n" ); document.write( "So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400. \n" ); document.write( " |