document.write( "Question 765582: if you put $2000 into an interest bearing account, where interest is compounded quarterly (4 times a year) at 6%, how long will it take for your money to triple?
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document.write( "use A=P(1+r/n)^nt
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document.write( "solve for t \r
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document.write( "help please!! \n" );
document.write( "
Algebra.Com's Answer #466264 by jim_thompson5910(35256) ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "A=P(1+r/n)^(nt)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "6000=2000(1+0.06/4)^(4*t)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "6000/2000 = (1+0.06/4)^(4*t)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3 = (1+0.06/4)^(4*t)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3 = (1.015)^(4*t)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log(3) = log((1.015)^(4*t))\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log(3) = 4*t*log(1.015)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log(3)/(4*log(1.015)) = t\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "t = log(3)/(4*log(1.015))\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "t = 18.4471905815477\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So it will take roughly 18.4471905815477 years.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note: round appropriately if needed\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |