document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=765571>Question 765571</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the value of x so that x, x + 2, and x + 3 are terms of a geometric sequence.\r<BR>\n" );
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document.write( "Thank you in advance! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #466254 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=466254\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> These terms are in a geometric sequence if you divide any term by the previous term and you get the same r value\r<BR>\n" );
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document.write( "(x + 2)/x = r\r<BR>\n" );
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document.write( "(x+3)/(x+2) = r\r<BR>\n" );
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document.write( "Equate the two and solve for x\r<BR>\n" );
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document.write( "(x + 2)/x = (x+3)/(x+2)\r<BR>\n" );
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document.write( "(x + 2)(x+2) = x(x+3)\r<BR>\n" );
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document.write( "x^2 + 4x + 4 = x^2 + 3x\r<BR>\n" );
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document.write( "x^2 + 4x + 4 - x^2 = x^2 + 3x - x^2\r<BR>\n" );
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document.write( "4x + 4 = 3x\r<BR>\n" );
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document.write( "4x = 3x - 4\r<BR>\n" );
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document.write( "4x - 3x =  - 4\r<BR>\n" );
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document.write( "x = - 4\r<BR>\n" );
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document.write( "So the answer is x = -4\r<BR>\n" );
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