document.write( "Question 765510: Please help me determine a formula for the nth term of a geometric sequence where term 1 = 4 and term 13 = 16 384 \n" ); document.write( "
Algebra.Com's Answer #466228 by ramkikk66(644)\"\" \"About 
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document.write( "1st term = 4, 13th term = 16384\r\n" );
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document.write( "In a geometric progression (GP), every term is got by multiplying the previous\r\n" );
document.write( "term by a common ratio (r).\r\n" );
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document.write( "So if a is the 1st term, r is the common ratio\r\n" );
document.write( "1st term = a\r\n" );
document.write( "2nd term = a*r\r\n" );
document.write( "3rd term = a*r*r = a*r^2\r\n" );
document.write( "In general, nth term will be \"a%2Ar%5E%28n-1%29\"\r\n" );
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document.write( "Here we need to find what is the common ratio.\r\n" );
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document.write( "a = 4, 13th term = \"4%2A%28r%29%5E%2812%29+=+16384\"\r\n" );
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document.write( "\"r%5E12+=+16384%2F4+=+4096\"\r\n" );
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document.write( "\"r+=+4096%5E%281%2F12%29+=+2\" (you can find it using a calculator, or by factorizing 4096)\r\n" );
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document.write( "So, a = 4 and r = 2 in this series.\r\n" );
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document.write( "Formula for nth term = \"4%2A2%5E%28n-1%29+=+2%5E2%2A2%5E%28n-1%29+=+2%5E%28n%2B1%29\"\r\n" );
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document.write( "Hope you got it :)\r\n" );
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