document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=765492>Question 765492</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have the question for my math homework right now of \"use identities of sine and cosine to find the value of theta given that cosine2theta=3/4, theta therminates in quadrant III.\" I am unsure how to answer this.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #466193 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=466193\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> use identities of sine and cosine to find the value <BR>\n" );
document.write( "of theta given that cosine(2theta) = 3/4, theta terminates in quadrant III<BR>\n" );
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document.write( "Take the cos^-1 of each side to get:<BR>\n" );
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document.write( "2theta = cos^-1(3/4) = 41.41 or 41.41+360 = 401.41 degrees<BR>\n" );
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document.write( "Then theta = 200.7 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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