document.write( "Question 765398: 1) Michael works at the EdHelper Juice company which makes juice. The company's most popular fruit juice contains 11% of real fruit juice and 89% of a non-fruit juice. How much of non-fruit juice shold be added to 11 liters of fruit juice to make the popular fruit juice?\r
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\n" ); document.write( "\n" ); document.write( "3) Jacob has three liters of 80% acid. How much acid should he add to make a solution that is 85% acid?\r
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\n" ); document.write( "\n" ); document.write( "10) Brianna has 55% silver alloy. Emma has a 25% silver alloy. They mellted their alloys to create 112 grams of a 40% silver alloy. How many grams was Brianna's alloy?
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Algebra.Com's Answer #466178 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
FRUIT JUICE\r
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\n" ); document.write( "\n" ); document.write( "n for amount of non-real juice
\n" ); document.write( "Formula is 11% real juice, 89% non-real juice
\n" ); document.write( "\"11%2F%2811%2Bn%29=11\" and this is a dilution.
\n" ); document.write( "Solve for n.\r
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\n" ); document.write( "\n" ); document.write( "SILVER ALLOY\r
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\n" ); document.write( "\n" ); document.write( "B = grams of the 55% alloy
\n" ); document.write( "E = grams of the 25% alloy\r
\n" ); document.write( "\n" ); document.write( "\"55B%2B25E=40%2A112\"
\n" ); document.write( "and
\n" ); document.write( "\"B%2BE=112\"\r
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\n" ); document.write( "\n" ); document.write( "That system can be simplified a bit by dividing the first equation by 5;
\n" ); document.write( "\"11B%2B5E=8%2A112\"
\n" ); document.write( "and
\n" ); document.write( "\"B%2BE=112\"
\n" ); document.write( "Solve the system for B and E.
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