document.write( "Question 765365: Solve for the value of k that will make the roots of the function be real and equal: f(x)=(K-2)x^(2)+3Kx+3K+6 \n" ); document.write( "

Algebra.Com's Answer #466153 by josgarithmetic(39617) $\"\"$ $\"About$

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Exercise is for using the discriminant. \r
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\n" ); document.write( "\n" ); document.write( " $\"%28%283k%29%5E2-4%28k-2%29%283k%2B6%29%29\"$ , the discriminant.\r
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\n" ); document.write( "\n" ); document.write( " $\"%289k%5E2-4%283k%5E2-12%29%29\"$
\n" ); document.write( " $\"%289k%5E2-12k%5E2%2B48%29\"$
\n" ); document.write( " $\"%28-3k%5E2%2B48%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "You want the discriminant to be 0 to make f(x) have only one solution. This solution will be real.\r
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\n" ); document.write( "\n" ); document.write( " $\"-3k%5E2%2B48=0\"$
\n" ); document.write( " $\"3k%5E2=48\"$
\n" ); document.write( " $\"k%5E2=24%2A2%2F3=8%2A2=16\"$
\n" ); document.write( " $\"highlight%28k=-4%29\"$ OR $\"highlight%28k=4%29\"$ \n" ); document.write( "

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