document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=765347>Question 765347</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help on this question please!!\r<BR>\n" );
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document.write( "{6, 1, -4, -9, ...}\r<BR>\n" );
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document.write( "Write a formula for the general term (the nth term) of the arithmetic sequence. Do not use a resursive formula </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #466115 by </B><A HREF=/tutors/aboutme.mpl?userid=ramkikk66><B>ramkikk66(644)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ramkikk66><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=466115\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is an arithmetic progression with first term as 6, and difference as -5.<BR>\n" );
document.write( "(i.e. each term is the previous term -5)\r<BR>\n" );
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document.write( "In any arithmetic progression, if 'a' is the first term, and the difference is d,\r<BR>\n" );
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document.write( "Second term = a + d<BR>\n" );
document.write( "3rd term = a + d + d = a + 2d<BR>\n" );
document.write( "4th term = a + 3d<BR>\n" );
document.write( "In general, nth term = a + (n-1)*d\r<BR>\n" );
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document.write( "So in the above series, nth term will be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6+-+5%2A%28n+-+1%29+=+11+-+5%2An ALIGN=MIDDLE  ALT=\"6+-+5%2A%28n+-+1%29+=+11+-+5%2An\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Hope you got it :) </SPAN>\n" );
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