document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=765366>Question 765366</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Martin’s Hardware is clearing out their inventory of bicycles and tricycles.  The clerk rolls all of the bicycles and tricycles outside and arranges them in a line on the sidewalk.  If the total number of bicycles and tricycles is 37 and the total number of wheels on all the bicycles and tricycles combined is 90, how many tricycles are in the line on the sidewalk? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #466114 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=466114\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Bicycles = x<BR>\n" );
document.write( "Tricycles = y<BR>\n" );
document.write( "x + y = 37....1<BR>\n" );
document.write( "2x + 3y = 90...2<BR>\n" );
document.write( "Multiply (1) by 3<BR>\n" );
document.write( "3x + 3y = 111...3<BR>\n" );
document.write( "2x + 3y = 90....2<BR>\n" );
document.write( "Subtract (2) from (3)<BR>\n" );
document.write( "x       = 21<BR>\n" );
document.write( "Substitute x = 21 in (1)<BR>\n" );
document.write( "x + y = 37<BR>\n" );
document.write( "21 + y = 37<BR>\n" );
document.write( "     y + 37 - 21<BR>\n" );
document.write( "     y = 16<BR>\n" );
document.write( "So, there are 21 bicycles and <BR>\n" );
document.write( "16 tricycles.<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );