document.write( "Question 765293: How much pure sodium must be mixed with 5o quarts of a 65% sodium solution to get a 75% sodium solution? \n" ); document.write( "

Algebra.Com's Answer #466086 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+x+\"$ = quarts of pure sodium needed
\n" ); document.write( " $\"+.65%2A50+=+32.5+\"$ quarts of pure sodium in 65% solution
\n" ); document.write( "-----------------
\n" ); document.write( " $\"+%28+x+%2B+32.5+%29+%2F+%28+x+%2B+50+%29++=+.75+\"$
\n" ); document.write( " $\"+x+%2B+32.5+=+.75%2A%28+x+%2B+50+%29+\"$
\n" ); document.write( " $\"+x+%2B+32.5+=+.75x+%2B+37.5+\"$
\n" ); document.write( " $\"+.25x+=+5+\"$
\n" ); document.write( " $\"+x+=+20+\"$
\n" ); document.write( "20 quarts of pure sodium are needed
\n" ); document.write( "check:
\n" ); document.write( " $\"+%28+x+%2B+32.5+%29+%2F+%28+x+%2B+50+%29++=+.75+\"$
\n" ); document.write( " $\"+%28+20+%2B+32.5+%29+%2F+%28+20+%2B+50+%29++=+.75+\"$
\n" ); document.write( " $\"+52.5+%2F+70+=+.75+\"$
\n" ); document.write( " $\"+52.5+=+.75%2A70+\"$
\n" ); document.write( " $\"+52.5+=+52.5+\"$
\n" ); document.write( "OK \n" ); document.write( "

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