document.write( "Question 765298: A 5 gallon radiator containing a mixture of water and antifreeze solution. When tested , it was found to have only 40% antifreeze. How much must be drained out so that the radiator will then contain the desire 50% antifreeze solution. \n" ); document.write( "
Algebra.Com's Answer #466065 by josgarithmetic(39620)![]() ![]() ![]() You can put this solution on YOUR website! The question really should be changed. How about this way:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A 5 gallon radiator containing a mixture of water and antifreeze solution. When tested , it was found to have only 40% antifreeze. How much must be drained out AND REPLACED WITH PURE ANTIFREEZE so that the radiator will then contain 5 GALLONS OF THE desired 50% antifreeze solution?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let v = the amount of solution to remove and then replaced with pure antifreeze\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Note that the desired final volume must be the same as the starting volume in the five-gallon tank.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Arithmetic steps to solving: \n" ); document.write( "(5*40+(100-40)v)/5=50 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |