document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=765201>Question 765201</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A random number generator generates numbers between 0 and 10.  Let random variable X be the number generated.  Suppose X has a uniform distribution.  What is the probability that the computer generates a number between 1 and 4?  Note: you must find the probability density function of X.\r<BR>\n" );
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document.write( "Would really like to see how I need to work this problem.  Thank you.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #466012 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=466012\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The probability density function of X which has a uniform distribution on [0, 10] is defined in the following manner:<BR>\n" );
document.write( "f(x;A,B) = 1 / (B-A); where x is > or = A and less than or = B, f(x;A,B) = 0 for all other values of x,<BR>\n" );
document.write( "now f(x;A,B) = 1 / (10 -0) = 1/10 for each number generated in [0, 10]<BR>\n" );
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document.write( "the probability that the computer generates a number between 1 and 4 is <BR>\n" );
document.write( "(4 - 1) / (10 - 0) = 3/10 = .30\r<BR>\n" );
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