document.write( "Question 765184: 4x + 12 = x^2\r
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Algebra.Com's Answer #466000 by rothauserc(4718)\"\" \"About 
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4x + 12 = x^2
\n" ); document.write( "subtract 4x and 12 from both sides of =
\n" ); document.write( "x^2 -4x -12 = 0
\n" ); document.write( "factor the equation
\n" ); document.write( "(x-6) * (x+2) = 0
\n" ); document.write( "x = 6 or -2 (this is because (x-6) = 0 or (x+2) = 0 )
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