document.write( "Question 765069: x-y=6 & xy=1 then x^3-y^3=? \n" ); document.write( "
Algebra.Com's Answer #465963 by ramkikk66(644)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "\r\n" );
document.write( "Use the identity: \"%28x+-+y%29%5E3+=+x%5E3+-+y%5E3+-+3%2Ax%2Ay%2A%28x+-+y%29\"\r\n" );
document.write( "\r\n" );
document.write( "Since we know x - y = 6 and xy = 1, substitute in the equation.\r\n" );
document.write( "\r\n" );
document.write( "\"6%5E3+=+x%5E3+-+y%5E3+-+3%2A1%2A6\"\r\n" );
document.write( "\r\n" );
document.write( "\"216+=+x%5E3+-+y%5E3+-+18\"\r\n" );
document.write( "\r\n" );
document.write( "\"x%5E3+-+y%5E3+=+234\"\r\n" );
document.write( "\r\n" );
document.write( ":)\r\n" );
document.write( "\r\n" );
document.write( "
\n" ); document.write( "
\n" );