document.write( "Question 765101: The formula for the height (in feet from the starting point) reached after t seconds by an object thrown upward at r feet per second is h=rt – 16t^2. So for an object thrown upward at 160ft/sec, h=160t-16t^2\r
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\n" ); document.write( "\n" ); document.write( "how high will the object be after 4 seconds?
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Algebra.Com's Answer #465961 by nerdybill(7384)\"\" \"About 
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The formula for the height (in feet from the starting point) reached after t seconds by an object thrown upward at r feet per second is h=rt – 16t^2. So for an object thrown upward at 160ft/sec, h=160t-16t^2
\n" ); document.write( "after how many seconds will the object first be 336ft above its starting point?
\n" ); document.write( "start with:
\n" ); document.write( "h=160t-16t^2
\n" ); document.write( "set h to 336 and solve for t:
\n" ); document.write( "336=160t-16t^2
\n" ); document.write( "dividing both sides by 16:
\n" ); document.write( "21 = 10t-t^2
\n" ); document.write( "t^2+21 = 10t
\n" ); document.write( "t^2-10t+21 = 0
\n" ); document.write( "(t-3)(t-7) = 0
\n" ); document.write( "t = {3, 7}
\n" ); document.write( "the object will be at 336 feet twice (once on the way up and again on the way down) at:
\n" ); document.write( "3 seconds and 7 seconds
\n" ); document.write( ".
\n" ); document.write( "how high will the object be after 4 seconds?
\n" ); document.write( "start with:
\n" ); document.write( "h=160t-16t^2
\n" ); document.write( "set t to 4 and solve for h:
\n" ); document.write( "h=160(4)-16(4)^2
\n" ); document.write( "h=640-16(16)
\n" ); document.write( "h=640-256
\n" ); document.write( "h= 384 feet
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