document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=59200>Question 59200</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two Planes leave the same airpot at 11:00 a.m., traveling in opposite directions.  One of the planes travels at a speed that is 150 mi/h faster than the other.  At 1:00 p.m., the lanes are 1900 miles apart.  Find the speed of the faster plane. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46593 by </B><A HREF=/tutors/aboutme.mpl?userid=303795><B>303795(602)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=303795><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46593\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the speed of the slower plane be x. The faster planes speed must be x+150.<BR>\n" );
document.write( "Their combined speed is 2x + 150 miles per hour.<BR>\n" );
document.write( "In two hours they travel 2(2x +150) miles<BR>\n" );
document.write( "so 2(2x + 150)= 1900<BR>\n" );
document.write( "2(2x + 150)= 1900<BR>\n" );
document.write( "4x + 300 = 1900<BR>\n" );
document.write( "4x = 1600<BR>\n" );
document.write( "x=400<BR>\n" );
document.write( "so the faster plane is travelling at 400+150=550 miles per hour. </SPAN>\n" );
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