document.write( "Question 765002: Please help me solve this word problem as I don't understand how to solve mixture problems.\r
\n" ); document.write( "\n" ); document.write( "What quantity of 70 per cent acid solution must be mixed with a 25 solution to produce 972 mL of a 50 per cent solution?
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Algebra.Com's Answer #465886 by lwsshak3(11628)\"\" \"About 
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Please help me solve this word problem as I don't understand how to solve mixture problems.
\n" ); document.write( "What quantity of 70 per cent acid solution must be mixed with a 25 solution to produce 972 mL of a 50 per cent solution?
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\n" ); document.write( "let x=quantity (mL) of 70% solution to be mixed
\n" ); document.write( "972-x=quantity (mL) of 25% solution to be mixed
\n" ); document.write( "quantity of acid in the two solutions=quantity of acid in the mixture
\n" ); document.write( "70%x+25%(972-x)=50%*972
\n" ); document.write( ".70x+243-.25x=486
\n" ); document.write( ".45x=243
\n" ); document.write( "x=540
\n" ); document.write( "972-x=432
\n" ); document.write( "quantity (mL) of 70% solution to be mixed=540 mL
\n" ); document.write( "quantity (mL) of 25% solution to be mixed=432 mL
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