document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=60559>Question 60559</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i do not knwo how to solve this can some one please assist me thank you\r<BR>\n" );
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document.write( "52. 2y^2 – 3y – 6 = 0\r<BR>\n" );
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document.write( "real and imaginary solutions to each equation. \r<BR>\n" );
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document.write( "104. x^-2 – 9x^-1 + 18 = 0\r<BR>\n" );
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document.write( "not sure if you solve them both the same way or not i have a hard time recognizing which way to solve problems. thank you  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46588 by </B><A HREF=/tutors/aboutme.mpl?userid=FadelSalem><B>FadelSalem(12)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=FadelSalem><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=FadelSalem><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46588\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2y^2 – 3y – 6 = 0<BR>\n" );
document.write( "Use the formula: x = [-b + - sqt(b^2 - 4 ac)]/2a<BR>\n" );
document.write( "y = [3 +or- sqt(9 + 48)]/4 = [3 +-sqrt 57]/4\r<BR>\n" );
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document.write( "x^-2 – 9x^-1 + 18 = 0<BR>\n" );
document.write( "(x^-1  -3)(x^-1  -6) = 0<BR>\n" );
document.write( "x^-1 =3  or x^-1  = 6<BR>\n" );
document.write( "so, x = 1/3   or  x = 1/6\r<BR>\n" );
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document.write( "Happy New Year<BR>\n" );
document.write( "Fadel Salem - Egypt<BR>\n" );
document.write( "fadelsalem@hotmail.com<BR>\n" );
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