document.write( "Question 764907: The coordinates of \"A\" and \"B\" are (2,-4) and (0,3) respectively. \"C\" is a point on the line \"L\" such that the area of the triangle \"ABC\" is \"8+unit%5E2\". Find the two possible equation of \"L\". \n" ); document.write( "
Algebra.Com's Answer #465877 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
Line AB is y=-(7/2)x+3, and the line perpendicular to it at point (0,3) is y=(2/7)x+3. The point (0,3) here was picked arbitrarily for convenience. \r
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\n" ); document.write( "\n" ); document.write( "Using segment AB as a base of the triangle, distance formula, steps here omitted,... the base AB is \"sqrt%2853%29\". \r
\n" ); document.write( "\n" ); document.write( "Triangle with 8 unit^2 will have an altitude value h, so that:
\n" ); document.write( "\"%281%2F2%29%28sqrt%2853%29%29%2Ah=8\"
\n" ); document.write( "\"highlight%28h=16%2Fsqrt%2853%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "What point is h units away from (0,3) and is on line y=(2/7)x+3?
\n" ); document.write( "That refers to another distance and the use of distance formula again.
\n" ); document.write( "We want those two, variable points of (x, (2/7)x+3).
\n" ); document.write( "Applying distance formula,
\n" ); document.write( "\"h=16%2Fsqrt%2853%29=sqrt%28%28x-0%29%5E2%2B%28%282%2F7%29x%2B3-3%29%5E2%29\"
\n" ); document.write( "which will simplify to:
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\n" ); document.write( "\"highlight%28x=-112%2F53%29\" or \"highlight%28x=112%2F53%29\"
\n" ); document.write( "From those two values, you can use \"y=%282%2F7%29x%2B3\" to determine the corresponding values for y.\r
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\n" ); document.write( "\n" ); document.write( "Can you finish the rest of the way to the needed line \"y=-%287%2F2%29x%2Bg\" for some y-intercept g ?\r
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\n" ); document.write( "Just to show final answer without the remaining steps,
\n" ); document.write( "lines wanted are:
\n" ); document.write( "\"highlight%28y=-%287%2F2%29x%2B519%2F53%29\" and \"highlight%28y=-%287%2F2%29x%2B11%29\"
\n" ); document.write( "and know that point C is really still a variable point.
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