document.write( "Question 764907: The coordinates of and
are (2,-4) and (0,3) respectively.
is a point on the line
such that the area of the triangle
is
. Find the two possible equation of
. \n" );
document.write( "
Algebra.Com's Answer #465877 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! Line AB is y=-(7/2)x+3, and the line perpendicular to it at point (0,3) is y=(2/7)x+3. The point (0,3) here was picked arbitrarily for convenience. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Using segment AB as a base of the triangle, distance formula, steps here omitted,... the base AB is \n" ); document.write( "\n" ); document.write( "Triangle with 8 unit^2 will have an altitude value h, so that: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "What point is h units away from (0,3) and is on line y=(2/7)x+3? \n" ); document.write( "That refers to another distance and the use of distance formula again. \n" ); document.write( "We want those two, variable points of (x, (2/7)x+3). \n" ); document.write( "Applying distance formula, \n" ); document.write( " \n" ); document.write( "which will simplify to: \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( "From those two values, you can use \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Can you finish the rest of the way to the needed line \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------------------------ \n" ); document.write( "Just to show final answer without the remaining steps, \n" ); document.write( "lines wanted are: \n" ); document.write( " \n" ); document.write( "and know that point C is really still a variable point. \n" ); document.write( " |