document.write( "Question 764988: F(x) =x^2+2x+4 ; g(x)=v(9-x) (When I do v() that is a square root symbol)
\n" ); document.write( "Find each of the following if it exists:\r
\n" ); document.write( "\n" ); document.write( "My question is (fg)(-7)
\n" ); document.write( "(-7^2+(2)(-7)+4)(v(9-(-7))
\n" ); document.write( "(-49-14+4)(v(16))
\n" ); document.write( "(-59)(4)
\n" ); document.write( "-236
\n" ); document.write( "I'm wondering if I figured this out correctly. The minus negative 7 in the square root is throwing me off I dont understand if i should add the 7 because there are two negatives or if I should subtract a negative 7 and also the negative 7 squared it throwing me off I'm confused about how I should count the negatives. Should I count it as -7^2 or (-7)^2? Thank you very much for your help.
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Algebra.Com's Answer #465866 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
\"F(x) =x^2+2x+4 ; g(x)=v(9-x) (When I do v() that is a square root symbol)\"\r
\n" ); document.write( "\n" ); document.write( "You mean this for the second function: g(x)=sqrt(9-x) or \"g%28x%29=sqrt%289-x%29\"\r
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\n" ); document.write( "\n" ); document.write( "You ask for help with the composition F of g, evaluated at x=-7.
\n" ); document.write( "First, form the composition:
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\n" ); document.write( "\"9-x%2B2%2Asqrt%289-x%29%2B4\"
\n" ); document.write( "\"-x%2B2%2Asqrt%289-x%29%2B13\"
\n" ); document.write( "\"highlight%28F%28g%28x%29%29=-x%2B2%2Asqrt%289-x%29%2B13%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now just let x=-7 and see what is the evaluation.
\n" ); document.write( "\"-%28-7%29%2B2%2Asqrt%2816%29%2B13=7%2B13%2B2%2A4=highlight%2828%29\"\r
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