document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=764989>Question 764989</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Okay. There's a rectangle with a perimeter of 38 inches. The length is 3 inches longer than the width. What is length?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #465863 by </B><A HREF=/tutors/aboutme.mpl?userid=hunk1412><B>hunk1412(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hunk1412><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=hunk1412><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=465863\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let lenth is L and breadth is B of rectangle<BR>\n" );
document.write( "as we know that the perimeter of rectangle is 2(L+B)<BR>\n" );
document.write( "so 2(L+B)=38 inches<BR>\n" );
document.write( "L+B=19<BR>\n" );
document.write( "as we seen that L=B+3<BR>\n" );
document.write( "put this value above we get<BR>\n" );
document.write( "B+3+B=19<BR>\n" );
document.write( "2B=16<BR>\n" );
document.write( "B=8<BR>\n" );
document.write( "so L=8+3=11<BR>\n" );
document.write( "so L=11 inches<BR>\n" );
document.write( "   B=8 inches </SPAN>\n" );
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