document.write( "Question 764950: if 1st 44 positive integers form a no. N as N=12345678.........424344 and N is divided by 45, then what is the remainder? \n" ); document.write( "
Algebra.Com's Answer #465843 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "for number to be divisible by 45 it should be divisible by both 5 and 9 \r
\n" ); document.write( "\n" ); document.write( "as you can see, last digit is \"4\" and we know that number should be divisible by both 5 and 9
\n" ); document.write( "for number to be divisible by \"5\" last digit should be \"0\" or \"5\"; so, we can say that reminder should be \"4\" because only if we deduct \"4\" last digit will be \"0\"\r
\n" ); document.write( "\n" ); document.write( "so, answer is: the remainder is \"4\"
\n" ); document.write( "
\n" ); document.write( "but to be sure, check the divisibility by \"9\" \r
\n" ); document.write( "\n" ); document.write( "in order to do that, we need to find the sum of the digits of N=12345678.........424344:\r
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "\n" ); document.write( "or, faster this way:\r
\n" ); document.write( "\n" ); document.write( "\"1-9=45%2B1%28of+10%29=46\"
\n" ); document.write( "\"11-20=9%2B45%2B2=56\"
\n" ); document.write( "\"21-30=18%2B45%2B3=66\"
\n" ); document.write( "\"31-40=27%2B45%2B4=76\"
\n" ); document.write( "\"41-44=16%2B10=26\"
\n" ); document.write( "so sum of digits is \"279\"\r
\n" ); document.write( "\n" ); document.write( "\"279%2F9=31\"; so, \"279\" is divisible by \"9\"
\n" ); document.write( "
\n" ); document.write( "since \"5\" and \"9\" are co-prime numbers, the number given number should also be divisible by \"5\"\r
\n" ); document.write( "\n" ); document.write( " dividing the number by \"5\" we get \"279%2F5+=55%2B4%2F5\";so, we got a remainder of \"4\"\r
\n" ); document.write( "\n" ); document.write( "so, your answer is: the remainder is \"4\"\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );