document.write( "Question 764872: An investor invested a total of $2,600 in two mutual funds. One fund earned a 4% profit while the other earned a 2% profit. If the investor's total profit was $84, how much was invested in each fund? \r
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Algebra.Com's Answer #465768 by mananth(16946)\"\" \"About 
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Part I 4.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 2.00% per annum ------------ Amount invested = y
\n" ); document.write( " 2600
\n" ); document.write( "Interest----- 84.00
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\n" ); document.write( "Part I 4.00% per annum ---x
\n" ); document.write( "Part II 2.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 2600 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "4.00% x + 2.00% y= 84
\n" ); document.write( "Multiply by 100
\n" ); document.write( "4 x + 2 y= 8400.00 --------2
\n" ); document.write( "Multiply (1) by -4
\n" ); document.write( "we get
\n" ); document.write( "-4 x -4 y= -10400.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x -2 y= -2000
\n" ); document.write( "divide by -2
\n" ); document.write( " y = 1000
\n" ); document.write( "Part I 4.00% $ 1600
\n" ); document.write( "Part II 2.00% $ 1000
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\n" ); document.write( "CHECK
\n" ); document.write( "1600 --------- 4.00% ------- 64.00
\n" ); document.write( "1000 ------------- 2.00% ------- 20.00
\n" ); document.write( "Total -------------------- 84.00
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