document.write( "Question 764822: State how many imaginary and real zeros the function has.\r
\n" ); document.write( "\n" ); document.write( "f(x) = x3 + 5x2 + x + 5
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #465743 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"f%28x%29+=+x%5E3+%2B+5x%5E2+%2B+x+%2B+5\"...group terms\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"f%28x%29+=%28+x%5E3++%2B+x%29+%2B+%285x%5E2%2B+5%29\"...factor\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29+=x%28+x%5E2++%2B+1%29+%2B+5%28x%5E2%2B+1%29\"\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29+=%28x+%2B+5%29%28x%5E2%2B+1%29\"\r
\n" ); document.write( "\n" ); document.write( "solutions: use zero product rule\r
\n" ); document.write( "\n" ); document.write( "\"%28x+%2B+5%29%28x%5E2%2B+1%29=0\"\r
\n" ); document.write( "\n" ); document.write( "if \"%28x+%2B+5%29=0\" => \"x=-5\".....one real zero, means the line crosses \"x-axis\" at (\"-5\",\"0\") \r
\n" ); document.write( "\n" ); document.write( "if \"x%5E2%2B+1=0\" => \"x%5E2=-1\".....=> \"x=sqrt%28-1%29\"=> \"x=i\" and \"x=-i\"...two imaginary zeros \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+25%2C+%28x+%2B+5%29%28x%5E2%2B+1%29%29+\" \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );