document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=764805>Question 764805</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ms. Rosse is a Head Nurse at TCH. Her patient wanted an update of her progress. The temperatures are normally distributed with mean 101.1F and the standard deviation is 1.8F. She reads a report that says that in 16 readings the patient’s mean temp was 102.2F. Find the probability that the mean patient’s temperature was at most 102.2F. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #465730 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=465730\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Ms. Rosse is a Head Nurse at TCH. Her patient wanted an update of her progress. The temperatures are normally distributed with mean 101.1F and the standard deviation is 1.8F. She reads a report that says that in 16 readings the patient’s mean temp was 102.2F. Find the probability that the mean patient’s temperature was at most 102.2F.<BR>\n" );
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document.write( "t(102.2) = (102.2-101.1)/[1.8/sqrt(16)] = 2.4444<BR>\n" );
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document.write( "P(temp > 102.2) = P(t > 2.4444 when df=15) = 0.0137<BR>\n" );
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document.write( "Cheers<BR>\n" );
document.write( "Stan H.<BR>\n" );
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