document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=764792>Question 764792</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A regular hexagon is inscribed in a circle. The radius of the circle is 12 cm.<BR>\n" );
document.write( "Determine the perimeter of the hexagon </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #465727 by </B><A HREF=/tutors/aboutme.mpl?userid=reviewermath><B>reviewermath(1029)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=reviewermath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=reviewermath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=465727\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28+400%2C+400%2C+-15%2C+15%2C+-15%2C+15%2Cred%28circle%28+0%2C+0%2C+12+%29%29%2C+line%2812%2C0%2C6%2C6%2Asqrt%283%29%29%2C+line%286%2C6%2Asqrt%283%29%2C-6%2C6%2Asqrt%283%29%29%2C+line%28-6%2C6%2Asqrt%283%29%2C-12%2C0%29%2C+line%28-12%2C0%2C-6%2C-6%2Asqrt%283%29%29%2Cline%28-6%2C-6%2Asqrt%283%29%2C6%2C-6%2Asqrt%283%29%29%2C+line%286%2C-6%2Asqrt%283%29%2C12%2C0%29%2Cblue%28line%280%2C0%2C-6%2C-6%2Asqrt%283%29%29%29%2Cblue%28line%280%2C0%2C6%2C-6%2Asqrt%283%29%29%29+%2Clocate%28-3%2C-5%2C%2212%22%29%2Clocate%281.5%2C-5%2C%2212%22%29%2C+locate%28-1%2C-9%2C%2212%22%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "An equilateral triangle is formed by joining the two radii (color blue) and the side of an inscribed hexagon.<BR>\n" );
document.write( "Since the radius is 12 cm, then each side of a hexagon measures 12 cm.<BR>\n" );
document.write( "The perimeter of the hexagon is 6 times 12 cm = 72 cm.\r<BR>\n" );
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document.write( "ANSWER: 72 cm </SPAN>\n" );
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