document.write( "Question 764774: If the sum of two numbers is 83 and the difference of the two numbers is 41, then the smaller number must be __ \n" ); document.write( "

Algebra.Com's Answer #465707 by MathLover1(20850) $\"\"$ $\"About$

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let the greater number be $\"x\"$ and the smaller number be $\"y\"$ \r
\n" ); document.write( "\n" ); document.write( "if the sum is $\"83\"$ , then $\"x%2By=83\"$ .....eq.1\r
\n" ); document.write( "\n" ); document.write( "and if the difference of the two numbers is $\"41\"$ ,then $\"x-y=41\"$ .....eq.2\r
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\n" ); document.write( "\n" ); document.write( "to find the smaller number, solve the system:\r
\n" ); document.write( "\n" ); document.write( " $\"x%2By=83\"$ .....eq.1
\n" ); document.write( " $\"x-y=41\"$ .....eq.2
\n" ); document.write( "___________________________\r
\n" ); document.write( "\n" ); document.write( " $\"x%2By=83\"$ .....eq.1....solve for $\"x\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=83-y\"$ .....plug it in eq.2\r
\n" ); document.write( "\n" ); document.write( " $\"83-y-y=41\"$ .....eq.2....solve for $\"y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"83-2y=41\"$
\n" ); document.write( " $\"83-41=2y\"$
\n" ); document.write( " $\"42=2y\"$
\n" ); document.write( " $\"42%2F2=y\"$
\n" ); document.write( " $\"highlight%2821=y%29\"$ ....so, the smaller number is $\"highlight%2821%29\"$ \r
\n" ); document.write( "\n" ); document.write( "now we can find greater number $\"x\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=83-21\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"highlight%28x=62%29\"$ ....the greater number is $\"highlight%2862%29\"$ \r
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