document.write( "Question 61684: The vertices of a triangle ae P(-1,-1) Q(2,1) R(3,-1). Find the equation of the altitude of triangle PQR drawn from Q.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "There is a meteor shower, one meteor appears at A(7,8) and disappears at B(1,4).
\n" ); document.write( "calculate the gradient of the meteor's flight path
\n" ); document.write( "and the acute angle between the flight path and the horizon (OX) correct to the nearest degree.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "A second meteor, on a parallel path, starts at c (6,2) and disappears below the horizon at D, Find the co-ordinates of D.
\n" ); document.write( "

Algebra.Com's Answer #46570 by venugopalramana(3286)\"\" \"About 
You can put this solution on YOUR website!
The vertices of a triangle ae P(-1,-1) Q(2,1) R(3,-1). Find the equation of the altitude of triangle PQR drawn from Q.
\n" ); document.write( "LET QA BE THE ALTITUDE.
\n" ); document.write( "IT IS PERPENDICULAR TO PR
\n" ); document.write( "SLOPE OF PR=[-1-(-1)]/[3-(-1)]=0
\n" ); document.write( "HENCE SLOPE OF QA IS -1/0 THAT IS -INFINITY
\n" ); document.write( "IT PASSES THROUGH Q (2,1).HENCE EQN. F ALTITUDE IS
\n" ); document.write( "X=1
\n" ); document.write( " There is a meteor shower, one meteor appears at A(7,8) and disappears at B(1,4).
\n" ); document.write( " calculate the gradient of the meteor's flight path
\n" ); document.write( " and the acute angle between the flight path and the horizon (OX) correct to the nearest degree.
\n" ); document.write( "SLOPE OF AB = (4-8)/(1-7)=-4/-6=2/3 IS THE GRADIENT OF HE METEOR' PATH.
\n" ); document.write( "ACUTE ANGLE = ARC TAN(2/3)=33.7 OR 34 DEGREES.\r
\n" ); document.write( "\n" ); document.write( " A second meteor, on a parallel path, starts at c (6,2) and disappears below the horizon at D, Find the co-ordinates of D.\r
\n" ); document.write( "\n" ); document.write( "PARALLEL LINE TO ABOVE WILL HAVE SAME SLOPE AS ABOVE .
\n" ); document.write( "IF D IS (H,K) , THEN
\n" ); document.write( "(K-2)/(H-6)=2/3
\n" ); document.write( "3(K-2)=2(H-6)
\n" ); document.write( "SINCE D IS GIVEN TO BE BELOW HORIZON,ASSUMING K TO BE ZERO,WE CAN FIND H
\n" ); document.write( "-6=-2(H-6)
\n" ); document.write( "2H=12+6=18
\n" ); document.write( "H=9
\n" ); document.write( "D IS (9,0)
\n" ); document.write( "
\n" );