document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=764732>Question 764732</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solving the square:\r<BR>\n" );
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document.write( "x^2+2x=48\r<BR>\n" );
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document.write( "I believe you add + 1 to both sides so x^2+2X+1=48+1 then I think you add the 48+1 to make 49. I am not sure where to go from there. Thank you for your help.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #465665 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=465665\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2 + 2x - 48 = 0<BR>\n" );
document.write( "x^2 + 2x.......-48<BR>\n" );
document.write( "x^2 + 2x + (2/2)^2.....  - 48<BR>\n" );
document.write( "(x + 1)^2.....  -1 - 48<BR>\n" );
document.write( "(x + 1)^2 - 49<BR>\n" );
document.write( "OR<BR>\n" );
document.write( "x^2 + 2x + 48 = 0<BR>\n" );
document.write( "x^2 + 2x.......+ 48<BR>\n" );
document.write( "x^2 + 2x + (2/2)^2.....+ 48<BR>\n" );
document.write( "(x + 1)^2.......-1 + 48<BR>\n" );
document.write( "(x + 1)^2 + 47<BR>\n" );
document.write( "If you add +1 to one side<BR>\n" );
document.write( "you must balance it up <BR>\n" );
document.write( "with -1 to the other side.<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
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