document.write( "Question 764715: The diagnol of a rectangle is 8 meters longer than the width. The length is 20 meters. Find the width of the rectangle. \n" ); document.write( "
| Algebra.Com's Answer #465662 by Cromlix(4381)     You can put this solution on YOUR website! Pythagoras. \n" ); document.write( "Width = x \n" ); document.write( "Diagonal = x + 8\r \n" ); document.write( "\n" ); document.write( "Length^2 + Width^2 = Diagonal^2 \n" ); document.write( "20^2 + x^2 = (x + 8)^2 \n" ); document.write( "400 + x^2 = x^2 + 16x + 64 \n" ); document.write( "Collect like terms \n" ); document.write( "16x - 336 = 0 \n" ); document.write( "16x = 336 \n" ); document.write( "x = 21m \n" ); document.write( "Width = 21m \n" ); document.write( "Hope this helps. \n" ); document.write( ":-) \n" ); document.write( " |