document.write( "Question 764715: The diagnol of a rectangle is 8 meters longer than the width. The length is 20 meters. Find the width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #465662 by Cromlix(4381)\"\" \"About 
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Pythagoras.
\n" ); document.write( "Width = x
\n" ); document.write( "Diagonal = x + 8\r
\n" ); document.write( "\n" ); document.write( "Length^2 + Width^2 = Diagonal^2
\n" ); document.write( "20^2 + x^2 = (x + 8)^2
\n" ); document.write( "400 + x^2 = x^2 + 16x + 64
\n" ); document.write( "Collect like terms
\n" ); document.write( "16x - 336 = 0
\n" ); document.write( "16x = 336
\n" ); document.write( "x = 21m
\n" ); document.write( "Width = 21m
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-)
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